Hardy-Weinberg Equilibrium

Hardy-Weinberg Equilibrium

Question:

The frequency of homozygotes in a diploid population is 0.68. Assuming that the population is in Hardy-Weinberg equilibrium, the frequencies of the two alleles are

  1. 1 and 0.9
  2. 2 and 0.8
  3. 4 and 0.6
  4. 5 and 0.5

Rephrasing the Question:

What is the equation for Hardy-Weinberg equilibrium?

Answer:

This is the option where the product of the two allele frequencies is 0.16, which is 0.2 and 0.8 (option 2).

Explanation:

Hardy-Weinberg Equilibrium

Recall that in a population in Hardy-Weinberg equilibrium, the frequencies of two alleles p and q follow the equation:

p2 + 2pq + q2 = 1

Here, p2 represents homozygotes of the p allele, q2 represents the homozygotes of the q allele, and pq represents heterozygotes.

The question tells us that the frequency of homozygotes (so both p homozygotes and q homozygotes combined) is 0.68. We can use this to find the value of pq.

p2 + 2pq + q2 = 1

(p2 + q2) + 2pq = 1

0.68 + 2pq = 1

2pq = 1 – 0.68

2pq = 0.32

pq = 0.16

So we simply choose the option where the product of p and q is 0.16, which is option 2 (0.2 x 0.8 = 0.16).

Sources:

5 thoughts on “Hardy-Weinberg Equilibrium”

  1. Thanks for sharing this informative post! As someone who enjoys PB77, I found your insights on PB77 to be really helpful. It’s always interesting to learn about new strategies and tips for maximizing winnings while staying responsible. Looking forward to trying out some of these techniques during my next visit to the PB77! Keep up the great work!

  2. This post is a masterpiece! Your storytelling prowess combined with your expertise makes for an incredibly captivating read. I’m grateful for the effort you put into crafting such thought-provoking content that challenges our perspectives and encourages us to delve deeper into the subject

    ipltata casino

Leave a Comment

Your email address will not be published.